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sc0rp1o21
02-26-2002, 01:13 AM
I'm unfamiliar with the whole ohm load that subs have like 4 ohms, 6 ohms, 8 ohms. how do you configure what the ohms are when you wire two subs (single voice coil) in parallel on the amp in a bridged set up?

Any explanations are greatly appreciated.

thanks

Impulse
02-26-2002, 06:23 AM
Here is the equation for adding resistances in prallel:

R1, R2=impedance of sub
1/R = total impedance

1/R = 1/R1 + 1/R2

so if you had two 4 ohm subs:

1/4 + 1/4 = 2/4
then take the inverse of 2/4 which is 4/2 = 2

So two 4 ohm subs in parallel will present a 2 ohm load to your amp.

For imedances in series just add them up. So wiring two 4 ohm subs in series will present an 8 ohm load to your amp.

sc0rp1o21
02-27-2002, 02:36 AM
that helps a great deal man...Thanks